Naturally occurring europium (Eu) consists of two isotopes with a mass of 151 and 153. 151/63 Eu has an abundance of 48.03% and 153/63 Eu has an abundance of 51.97%. What is the atomic mass of europium?

Answer 1

The atomic mass of europium is 152 u.

Method 1

Assume that you have 10 000 atoms of Eu.

Then you have 4803 atoms of #""_63^151"Eu"# and 5197 atoms of #""_63^153"Eu"#.

Mass of #""_63^151"Eu"# = 4803 × 151 u = 725 253 u

Mass of #""_63^153"Eu"# = 5197 × 153 u = 795 141 u

Mass of 10 000 atoms = 1 520 394 u

Average mass = #(1520394"u")/10000# = 152 u

Method 2

#""_63^151"Eu"#: 48.03 % × 151 u = 72.5253 u

#""_63^153"Eu"#: 51.97 % × 153 u = 79.5141 u

Total = "152.0394 u" = 152 u

Note: In both methods, the answer can have only three significant figures, because that is all you gave for masses of the two isotopes.

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Answer 2

The weighted average of the masses of europium's isotopes multiplied by their respective abundances yields the atomic mass of the element: atomic mass = (mass of isotope 1 * abundance of isotope 1) + (mass of isotope 2 * abundance of isotope 2)... atomic mass = (151 * 0.4803) + (153 * 0.5197)... atomic mass ≈ (72.6153) + (79.7031)......... \

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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