Mrs. Barns earns a base salary of plus a 1.5% commission on sales. Her total sales one year were $700,000. How do you find her total pay for the year?

Answer 1

See a solution process below:

The total salary of Mrs. Barns is as follows:

#t = b + (c * s)#

Where:

#t# is Mrs. Barns total pay for the year
#b# is Mrs. Barns base salary
#c# is Mrs. Barns commission rate. In this problem: 1.5%. "Percent" or "%" means "out of 100" or "per 100", Therefore 1.5% can be written as #1.5/100# or #15/1000#.
#s# is the total sales for the year. In this problem: $700,000

When the data from the problem is substituted, it yields:

#t = b + (15/1000 * $700,000)#
#t = b + ($10,500,000)/1000#
#t = b + $10,500#

Mrs. barns total pay would be the $10,500 from commissions plus her base salary.

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Answer 2

To find Mrs. Barns's total pay for the year, you would first calculate her commission by multiplying her total sales (700,000)bythecommissionrate(1.5700,000) by the commission rate (1.5% or 0.015). Then, add her base salary to the commission to get the total pay for the year. So, her commission would be 700,000 * 0.015 = 10,500.Addingherbasesalarytothecommission,thetotalpayfortheyearwouldbe10,500. Adding her base salary to the commission, the total pay for the year would be 10,500 + base salary.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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