Mg(OH)2 has a solubility of 9.0x10^-5 M. What is the value of Ksp for Mg(OH)2?

Answer 1

#K_"sp" = 2.9 × 10^"-12"#

The equilibrium's chemical equation is

#color(white)(mmmmmm)"Mg(OH)"_2"(s)" ⇌ "Mg"^(2+)"(aq)" + 2"OH"^"-""(aq)"# #"E:/mol·L"^"-1" color(white)(mmmmmmmmllm)x color(white)(mmmmmll)2x#

#K_"sp" = ["Mg"^(2+)]["OH"^"-"]^2 = x(2x)^2 = 4x^3#

#x = 9.0 × 10^"-5"#

∴ #K_"sp" = = 4(9.0 × 10^"-5")^3 = 2.9 × 10^"-12"#

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Answer 2

Wyatt Adkins

The Ksp for Mg(OH)2 is 8.1 x 10^-12.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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