Mavis is 5 years older than her brother. Five years ago she was 2 times older than her brother. How old is each now?

Question

Savannah Anderson · Accepted Answer

Mavis is now 15 years old and his brother 10 years old.

let Mavis's brother age now is A , So Marvis age is A+5 5 years ago, Marvis brother's age was A-5, Marvis's age was 2 times his brother's, so Marvis' age was 2(A-5) Five years ago, Marvis' age was 2(A-5), now 5 years have passed, his age is 2(A-5) +5 = A+5. #2(A-5)+5 = A+5# #2A-10+5=A+5# #2A-5=A+5# #A=10# #A+5=15#

Abigail Allen · Answer

The brother is 10 years old, Mavis is 15 years old.

We are working with 2 people and 2 periods of time; Mavis and her brother, and their ages now and 5 years ago. Her brother is younger - let his age be #color(blue)( x)# years Mavis is 5 years older than her brother (ADD 5) For both of them, their ages were #color(lime)("5 years LESS")#, 5 years ago. Write an expression for each person for each time. #color(white)(xxxxxxx) 5 " years ago" color(white)(x) larr color(lime)((-5)) larr color(white)(x) "present"# #"Mavis":color(white)(xx)(x+5)-5 = color(red)(x) color(white)(xxxxxxxx)(x+5)# #"Brother":color(white)(xx)color(red)((x-5)) color(white)(xxxxxxxxxxxxx)color(blue)(x)# The information we are given shows the relationship between their ages 5 years ago - shown in red. At that time, she was TWICE as old as he was. Form an equation. Do not multiply her age by 2!! 2 x younger age = older age # 2(x-5) = x# #2x-10=x# #color(blue)( x= 10) larr # this is the brother's present age. The brother is 10 years old, Mavis is 15 years old. Let's check: #color(white)(xxxxxxx) 5 " years ago" color(white)(x) larr color(lime)((-5)) larr color(white)(x) "present"# #"Mavis":color(white)(xxxxxxx)10 color(white)(xxxxxxxxxxxxx)15# #"Brother":color(white)(xxxxxx)color(red)(5) color(white)(xxxxxxxxxxxxx)color(blue)(10)# #2 xx5 = 10#

Genesis Allen · Answer

undefined Mavis is 10 years old and her brother is 5 years old.