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Logloglog base x (81) = 1 , find x ?

Answer 1

Serenity Jones

#x = 81#

View the process for solving below.

#log_x 81 = 1#

Recall;

#log_b a = c#

#a = b^c#

Hence;

#81 = x^1#

#81 = x#

Therefore, #x = 81#

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Answer 2

Anna Allen

To find (x) when given (\log_{x}(\log_{x}(\log_{x}(81))) = 1), we'll use the properties of logarithms.

Given: (\log_{x}(\log_{x}(\log_{x}(81))) = 1)

We know that (\log_{x}(x) = 1) for any positive base (x), so we can rewrite (\log_{x}(\log_{x}(\log_{x}(81)))) as (x).

Therefore, we have (x = 81).

So, (x = 81).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.