#lim_(x rarr 4) (3 - sqrt(5 + x))/(1- sqrt(5 - x)) = ?#

Answer 1

The limit is #-1/3#

It is similar to both

#lim_(xrarr4)(3-sqrt(5+x))/(x-4)# and to #lim_(xrarr4)(x-4)/(1-sqrt(5-x))#

but both in one expression.

So multiply #(3-sqrt(5+x))/(1-sqrt(5-x))# by
#((3+sqrt(5+x)))/((3+sqrt(5+x))) * ((1+sqrt(5-x)))/((1+sqrt(5-x)))# to get:
#lim_(xrarr4)((9-(5+x))(1+sqrt(5-x)))/((3+sqrt(5+x))(1-(5-x))#
# = lim_(xrarr4)((4-x)(1+sqrt(5-x)))/((3+sqrt(5+x))(-(4-x))#
# = lim_(xrarr4)(-(1+sqrt(5-x)))/(3+sqrt(5+x))#
# = (-(1+sqrt1))/(3+sqrt9) = -2/6 = -1/3#
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Answer 2

The limit should approach -1/3, I screwed up the original answer.

#lim_(x rarr 4) (3-sqrt(5+x))/(1-sqrt(5-x))#

first multiply the top and bottom by the conjugate of the numerator and the conjugate of the denominator

#(3-sqrt(5+x))/(1-sqrt(5-x))*#

#(3+sqrt(5+x))/(3+sqrt(5+x))*(1+sqrt(5-x))/(1+sqrt(5-x))#

# = (4-x)/(-(4-x))*(1+sqrt(5-x))/(3+sqrt(5+x)) #

# =-(1+sqrt(5-x))/(3+sqrt(5+x)) #

plug in the limit value to get your answer:

# =-(1+sqrt(5-4))/(3+sqrt(5+4)) #
# =-(1+1)/(3+3) = -2/6 = -1/3 #

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Answer 3

The limit of (3 - sqrt(5 + x))/(1 - sqrt(5 - x)) as x approaches 4 is 2.

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Answer 4

To find the limit of the given function as x approaches 4:

lim(x→4) (3 - √(5 + x))/(1 - √(5 - x))

We first need to observe that as x approaches 4, both denominators of the fractions will approach 0. This suggests that we may need to rationalize the fractions to simplify the expression.

Multiplying the numerator and denominator of the fraction by the conjugate of the denominator to rationalize:

lim(x→4) [(3 - √(5 + x))(1 + √(5 - x))]/[(1 - √(5 - x))(1 + √(5 - x))]

Expanding the numerator and denominator:

lim(x→4) [3(1) + 3√(5 - x) - √(5 + x) - (5 - x)] / [1 - (5 - x)]

Simplify:

lim(x→4) [3 + 3√(5 - x) - √(5 + x) - 5 + x] / [6 - x]

Combine like terms:

lim(x→4) [x - 2 + 3√(5 - x) - √(5 + x)] / [6 - x]

Now, we can directly substitute x = 4 into the expression:

[4 - 2 + 3√(5 - 4) - √(5 + 4)] / [6 - 4]

[2 + 3√1 - √9] / 2

[2 + 3 - 3] / 2

2/2

1

So, lim(x→4) (3 - √(5 + x))/(1 - √(5 - x)) = 1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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