# Lim (X^3+8/x+2). ? X=-2

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The sum of two cubes is the factor numerator.

Factors that cancel:

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The limit of ( \frac{x^3 + 8}{x + 2} ) as ( x ) approaches ( -2 ) is ( 0 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What are the vertical asymptotes for the graph of #y=(x+3)/((x-2)(x+5))#?
- How do you find the limit of #(2x^2-x-3)/(x+1)# as x approaches -1?
- What is the limit of #(x^3 -1)/(x^2+2x-3)# as x approaches 1?
- How do you find the limit of #(4x^2)/(x-2)# as x approaches 2?
- How do you evaluate # [ (1/x) - (1/(x^(2)+x) ) ]# as x approaches 0?

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