# Let R be the first quadrant region enclosed by the graph of #y= 2e^-x# and the line x=k, how od you find the area of R in terms of k?

Integrate

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To find the area of the region ( R ) enclosed by the graph of ( y = 2e^{-x} ) and the line ( x = k ) in the first quadrant, you need to integrate the function ( 2e^{-x} ) with respect to ( x ) over the interval from ( x = 0 ) to ( x = k ). The area of ( R ) in terms of ( k ) can be expressed as follows:

[ \text{Area of } R = \int_{0}^{k} 2e^{-x} , dx ]

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