Let M be a matrix and u and v vectors: #M =[(a, b),(c, d)], v = [(x), (y)], u =[(w), (z)].# (a) Propose a definition for #u + v#. (b) Show that your definition obeys #Mv + Mu = M(u + v)#?
Definition of addition of vectors, multiplication of a matrix by a vector and proof of distributive law are below.
End of proof.
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(a) The definition of ( u + v ) for vectors ( u ) and ( v ) is:
[ u + v = \begin{bmatrix} w + x \ z + y \end{bmatrix} ]
(b) To show that this definition obeys ( Mv + Mu = M(u + v) ), we first compute each side:
[ Mv = M \begin{bmatrix} x \ y \end{bmatrix} = \begin{bmatrix} ax + by \ cx + dy \end{bmatrix} ]
[ Mu = M \begin{bmatrix} w \ z \end{bmatrix} = \begin{bmatrix} aw + bz \ cw + dz \end{bmatrix} ]
[ u + v = \begin{bmatrix} w + x \ z + y \end{bmatrix} ]
Now, we compute ( M(u + v) ):
[ M(u + v) = M \begin{bmatrix} w + x \ z + y \end{bmatrix} = \begin{bmatrix} a(w + x) + b(z + y) \ c(w + x) + d(z + y) \end{bmatrix} ]
Expanding, we get:
[ = \begin{bmatrix} aw + ax + bz + by \ cw + cx + dz + dy \end{bmatrix} ]
[ = \begin{bmatrix} aw + bz + (ax + by) \ cw + dz + (cx + dy) \end{bmatrix} ]
[ = \begin{bmatrix} ax + by \ cx + dy \end{bmatrix} + \begin{bmatrix} aw + bz \ cw + dz \end{bmatrix} ]
[ = Mv + Mu ]
Therefore, ( Mv + Mu = M(u + v) ), showing that the proposed definition obeys this equality.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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