# Let #F(x)=int_(0)^xsqrt(1+t^2)dt# how to find #F'(x)#?

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To find ( F'(x) ) for the function ( F(x) = \int_0^x \sqrt{1 + t^2} , dt ), you can apply the Fundamental Theorem of Calculus, which states that if ( F(x) ) is the integral of ( f(x) ), then ( F'(x) = f(x) ).

So, in this case, ( F'(x) = \sqrt{1 + x^2} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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