Let #f(x)=9x-8#, how do you find #(fof)(5)#?

Answer 1

Assuming you mean #f(5)#, then #f(5)=37#

If we have #f(x)# as some transformation applied to #x#, then #f(a)# will be the same transformation but applied to #a#.

So if #f(x)=2x^2+9#, then #f(a)=2a^2+9#. And if we say #a=5#, then #f(a)=2(5)^2+9=59#

So, using this principle, #f(5) = 9(5)-8=37#

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Answer 2

Eva Abramson

To find ( (f \circ f)(5) ), first find ( f(5) ), then substitute the result into the function ( f(x) ) again.

( f(5) = 9(5) - 8 = 45 - 8 = 37 )
( f(37) = 9(37) - 8 = 333 - 8 = 325 )

So, ( (f \circ f)(5) = 325 ).

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Answer from HIX Tutor

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