Let #f(x)=2x^2+2#, how do you find f(0.3)?

Answer 1

#f(x) = y =2.18#

#f(color(red)(x)) = 2x^2 +2" "larr# the right side shows what is done to #x# #color(white)(x)darr# #f(color(red)(0.3))" "larr# you are told that #x# has the value #0.3#

#f(color(red)(x)) = 2color(red)(x^2) +2#

#f(color(red)(0.3)) = 2color(red)((0.3^2)) +2#

#color(white)(xxxx) =2 xx 0.09 +2#

#color(white)(xxxx) =2.18#

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Answer 2

Ethan Adkins

To find ( f(0.3) ), simply substitute ( x = 0.3 ) into the function ( f(x) = 2x^2 + 2 ).

( f(0.3) = 2(0.3)^2 + 2 )

( f(0.3) = 2(0.09) + 2 )

( f(0.3) = 0.18 + 2 )

( f(0.3) = 2.18 )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.