# Let #f(x)=1-x# and #g(x)= x^2# and #h(x)= 1/x#, how do you find g(f(h(x)))?

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To find ( g(f(h(x))) ), follow these steps:

- Substitute ( h(x) ) into ( f(x) ), obtaining ( f(h(x)) ).
- Substitute the result from step 1 into ( g(x) ), obtaining ( g(f(h(x))) ).

Let's proceed with the calculations:

- ( f(h(x)) = 1 - h(x) = 1 - \frac{1}{x} = \frac{x-1}{x} )
- ( g(f(h(x))) = (f(h(x)))^2 = \left(\frac{x-1}{x}\right)^2 = \frac{(x-1)^2}{x^2} )

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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