Job places a dot on a coordinate play at (-10,-4) he wants to place another dot across the y-axis and it must be 14 points away where is he going to place it?

Answer 1
Let the coordinates of the dot placed on y-axis 14point away from #(-10,-4)# be #(0,a)#

Hence we can write

#sqrt(10^2+(a+4)^2)=14#
#=>100+(a+4)^2=196#
#=>(a+4)^2=96#
#=>a+4=pmsqrt96#
#=>a+4=pm4sqrt6#
#=>a=-4pm4sqrt6#

Hence the two possible positions are

#(0,-4-4sqrt6)and (0,-4+4sqrt6)#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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