Jessie's Canoes rents canoes for $20 for the canoe plus $35 per hour. You do not want to spend more than $150. What is the maximum number of hours that you can afford to rent a canoe?

Answer 1

The maximum number of hours we could rent the canoe would be 4 hours.

First, let's write the formula for the cost of renting a canoe from Jessie:

#C = 20 + 35h# where #C# is the total cost and #h# is the number of hours you rent the canoe.

Because we don't want to spend "MORE" than $150 this will become an inequality.

We need to solve:

#20 + 35h <= 150#
#20 - 20 + 35h <= 150 - 20#
#0 + 35h <= 130#
#35h < 150#
#(35h)/35 <= 150/35#
#h <= 4.3#

The maximum number of hours we could rent the canoe would be 4 hours.

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Answer 2

To find the maximum number of hours you can afford to rent a canoe from Jessie's Canoes, set up an inequality representing the total cost not exceeding $150:

(20 + 35h \leq 150)

Where (h) represents the number of hours rented.

Now, solve for (h):

(35h \leq 150 - 20)

(35h \leq 130)

(h \leq \frac{130}{35})

(h \leq 3.71)

Since you can't rent a fraction of an hour, the maximum number of hours you can afford to rent a canoe is 3 hours.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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