Jay made 8 of 10 free throws. Kim made 25 of 45. Who made free throws at the better rate?

Question

Gabriel Agustin · Accepted Answer

Jay had the better rate of free throws

Jay's success rate was #8/10=80%# Kim's success rate was #25/45=5/9=55.bar5%#

Genesis Amaya · Answer

undefined To determine who made free throws at the better rate, we can calculate the free throw percentage for each person.

For Jay:
$$ \text{Free throw percentage for Jay} = \frac{\text{Number of successful free throws by Jay}}{\text{Total number of attempted free throws by Jay}} \times 100 $$

For Kim:
$$ \text{Free throw percentage for Kim} = \frac{\text{Number of successful free throws by Kim}}{\text{Total number of attempted free throws by Kim}} \times 100 $$

Then, we compare their free throw percentages to determine who had the better rate.

For Jay:
$$ \text{Free throw percentage for Jay} = \frac{8}{10} \times 100 = 80\% $$

For Kim:
$$ \text{Free throw percentage for Kim} = \frac{25}{45} \times 100 \approx 55.56\% $$

Since Jay has a free throw percentage of 80%, which is higher than Kim's approximately 55.56%, Jay made free throws at the better rate.

Cameron Arnold · Answer

undefined Kim made free throws at a better rate than Jay. Jay's free throw percentage is 80% (8 out of 10), while Kim's free throw percentage is approximately 55.56% (25 out of 45).