Jacques can buy six CDs and three video cassettes for $163.7 or he can buy nine CDs and two video cassettes for $200.53. How do you find the price of one video cassette?

Question

Abigail Allen · Accepted Answer

I got: #$18.01# for the VHS and #$18.28# for the CDs.

Let us call the price of CDs #c# and of the Videos #v#; we can write: #6c+3v=163.7# #9c+2v=200.53# we can isolate #c# from the first and substitute into the second: #c=(163.7-3v)/6# and: #9(163.7-3v)/6+2v=200.53# #1473.3-27v+12v=1203.18# #v=18.01# and so: #c=(163.7-3*18.01)/6=18.28# Considering that nowadays it is almost impossible to find video cassettes and even CDs are difficult to come by....I suspect the exercise is quite old!

Genesis Allen · Answer

undefined To find the price of one video cassette, we can set up a system of equations using the given information. Let $ x $ be the price of one CD and $ y $ be the price of one video cassette.

From the first scenario:
$$ 6x + 3y = 163.7 $$

From the second scenario:
$$ 9x + 2y = 200.53 $$

Now, we can solve this system of equations to find the value of $ y $, which represents the price of one video cassette.