Is #y = 2x + 5# a direct variation and if so, how do you find the constant?
Yes, it is direct variation. The constant is 2
A direct variation always gives a straight line graph and can be expressed as y =ax + b where a and b are constants. a represents the slope of the line - the bigger it's value the steeper the slope. b is the value of y when x = 0 and is therefore where the line crosses the vertical axis. b is the value normally referred to as the constant and a as the slope. Therefore in this case the constant is 5.
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No, ( y = 2x + 5 ) is not a direct variation because it doesn't follow the form ( y = kx ). In direct variation equations, the variable ( y ) is directly proportional to the variable ( x ), with a constant of proportionality represented by ( k ). If ( y = 2x + 5 ) were a direct variation, it would be in the form ( y = kx ), where ( k ) is the constant of proportionality. However, in this equation, the term ( 5 ) is added to ( 2x ), indicating that the relationship between ( x ) and ( y ) is not directly proportional.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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