Is the point (-5,-27) on the line y=4x+7? And why?

Answer 1

See a solution process below:

To determine if the point #(-5, -27)# is on the line #y = 4x + 7#, substitute #-5# (the #x# value in the point) for #x# in the equation and calculate #y#.

If, #y = -27# after the substitution and calculation then the point is on the line.

If, #y != -27# after the substitution and calculation then the point is not on the line.

#y = 4x + 7# becomes:

#y = (4 xx -5) + 7#

#y = -20 + 7#

#y = -13#

Because #-13# is not equal to #-27# the point is not on the line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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