Is the function #f(X) = 4X^2 + X^4 -120# even, odd or neither?

Answer 1

Even function

Given function:

#f(x)=4x^2+x^4-120#
#\implies f(-x)=4(-x)^2+(-x)^4-120#
#=4x^2+x^4-120#
#=f(x)#
#\because f(-x)=f(x)# hence the given function is even function
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Answer 2

The function f(x) = 4x^2 + x^4 - 120 is neither even nor odd.

For a function to be even, it must satisfy the condition f(x) = f(-x) for all x in its domain. For a function to be odd, it must satisfy the condition f(x) = -f(-x) for all x in its domain.

Checking the given function: f(x) = 4x^2 + x^4 - 120 f(-x) = 4(-x)^2 + (-x)^4 - 120 = 4x^2 + x^4 - 120

This shows that f(x) = f(-x), which means the function is even.

Checking the condition for odd function: f(x) = 4x^2 + x^4 - 120 -f(-x) = -[4(-x)^2 + (-x)^4 - 120] = -[4x^2 + x^4 - 120] = -f(x)

Since f(x) is not equal to -f(-x), the function is not odd. Hence, the function f(x) = 4x^2 + x^4 - 120 is neither even nor odd.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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