Is the following statement True or False: " f'(x) exists for all real numbers x and f'(x) is never 0, then f(1) can not be equal to f(5). "?

Answer 1

It is true.

I'll try to show a line of thought that can lead us to a way to find the answer to the question.

The question asks something about #f(1)# and #f(5)#.
We know that #f'(x)# exists for all real #x#. (#f# is differentiable at every real #x#.)
We also know that differentiability implies continuity, so we can conclude that #f# is continuous at every real number.

We know some things about continuous functions and some things about differentiable functions.

Again, we are asked something about #f(1)# and #f(5)#, so we might now think about the closed interval #[1,5]#.
Since #f# is continuous and differentiable on #[1,5]# we have some theorems that apply to #f#.
Two of those theorems involve #f'(x)#, namely Rolle's Theorem and the Mean Value Theorem.
Using either theorem, we can conclude that if #f(1)# were equal to #f(5)#, then there would have to be a #c# in #(1,5)# with #f'(c) = 0#.
But there is no such #c#, so #f(1)# cannot be equal to #f(5)#.
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Answer 2
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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