Is the following equation balanced? NH2CH2COOH (s) + 9/4 O2 --> 2 CO2 (s) + 5/2 H2O (l) + 1/2 N2 (g)

Answer 1

The correct equation is #"4NH"_2"CH"_2"COOH(s)" + "9O"_2("g")"##rarr##"8CO"_2("g") + 10"H"_2"O"("l")" + 2N"_2"# .

The equation is not balanced; only whole number coefficients should be present in a balanced equation.

#"NH"_2"CH"_2"COOH(s)" + "9/4O"_2("g")"##rarr##"2CO"_2("g") + "5/2H"_2"O"("l") + "1/2N"_2("g")"#

Multiply all of the coefficients by 4 to find the common denominator of the fraction coefficients.

#"4NH"_2"CH"_2"COOH(s)" + "9O"_2("g")"##rarr##"8CO"_2("g") + (5*4)/2"H"_2"O"("l")" + (1*4)/2N_2#

The fractions on the right side of the equation should be made simpler.

#"4NH"_2"CH"_2"COOH(s)" + "9O"_2("g")"##rarr##"8CO"_2("g") + 20/2"H"_2"O"("l")" + 4/2N_2#

Cut down on the fractions on the right.

#"4NH"_2"CH"_2"COOH(s)" + "9O"_2("g")"##rarr##"8CO"_2("g") + 10"H"_2"O"("l")" + 2N"_2"#
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Answer 2

No, the equation is not balanced.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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