Is it true that the stronger the intermolecular interactions the higher the vapor pressure?

Question

Peyton Adams · Accepted Answer

The reverse is true. The stronger the intermolecular interaction, the weaker the vapour pressure.

It makes intuitive sense that liquids with strong intermolecular interaction—like water, which has remarkably strong intermolecular interaction for a molecule of its size—have low vapour pressures. Conversely, liquids with weaker intermolecular interaction, like the alkane series, tend to have lower boiling points and, consequently, higher vapour pressures. Here we define boiling point as the temperature at which the vapour pressure of the liquid becomes equal to the ambient pressure, and bubbles of vapour form directly in the liquid. The normal boiling point is specified when the ambient pressure is #1# #atm#, and thus the vapour pressure of the liquid, at its normal boiling point, is #1*atm#.

Caleb Adams · Answer

undefined No, that statement is not true. Stronger intermolecular interactions typically lead to lower vapor pressure, as molecules are less likely to escape from the liquid phase into the gas phase when there are stronger attractions between them.