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Is it possible to factor #y=2x^2-16x+32 #? If so, what are the factors?

Answer 1

Savannah Anderson

#x=4#

#y=2x^2-16x+32#

#y=2(x^2-8x+16)#

#y=2(x-4)^2#

Therefore, the factor is #x=4#. Note that this is a double root

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Answer 2

Eva Adamson

Yes, it is possible to factor the quadratic equation ( y = 2x^2 - 16x + 32 ). The factors are:

[ y = 2(x - 4)^2 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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