Is #f(x)=(x-3)/sqrt(x+3) # increasing or decreasing at #x=5 #?

Answer 1

We start by differentiating.

Let #y = u^(1/2)# and #u = x + 3#. By the power rule, #y' = 1/2u^(-1/2) = 1/(2u^(1/2))# and #u' = 1#

By the chain rule:

#dy/dx= dy/(du) xx (du)/dx#
#dy/dx = 1/(2u^(1/2)) xx 1#
#dy/dx = 1/(2(x + 3)^(1/2))#
For #f'(x)#, we find the derivative by the quotient rule:
#f'(x) = (1sqrt(x+ 3) - (x - 3)1/(2(x + 3)^(1/2)))/(sqrt(x+ 3))^2#
#f'(x) = (sqrt(x + 3) - (x - 3)/(2(x + 3)^(1/2)))/(x + 3)#
#f'(x) = ((2sqrt(x + 3)sqrt(x+ 3) - x + 3)/(2(x + 3)^(1/2)))/(x+ 3)#
#f'(x) = ((2(x + 3) - x + 3)/(2(x+ 3)^(1/2)))/(x + 3)#
#f'(x) = ((2x + 6 - x + 3)/(2(x + 3)^(1/2)))/(x + 3)#
#f'(x) = (x + 9)/(2(x + 3)^(1/2)x + 3)#
#f'(x) = (x + 9)/(2(x + 3)^(3/2))#
Now, if the function is increasing at the point #x = a#, then #f'(a) > 0#. If the function is decreasing at #x= a#, then #f'(a) < 0#.
#f'(5) = (5 + 9)/(2(5 + 3)^(3/2))#
#f'(5) = 14/(2sqrt(512))#
#f'(5) = 14/(2(16)sqrt(2))#
#f'(5) = 14/(32sqrt(2)#
#f'(5) = 7/(16sqrt(2))#
What matters is that the above value is positive. Hence, #f(x)# is increasing at #x = 5#.

Hopefully this helps!

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Answer 2

To determine if ( f(x) = \frac{x - 3}{\sqrt{x + 3}} ) is increasing or decreasing at ( x = 5 ), we need to evaluate the derivative of ( f(x) ) and then determine its sign at ( x = 5 ).

The derivative of ( f(x) ) with respect to ( x ) is given by:

[ f'(x) = \frac{d}{dx}\left(\frac{x - 3}{\sqrt{x + 3}}\right) ]

Using the quotient rule and the chain rule, we find:

[ f'(x) = \frac{(x + 3)^\frac{-3}{2}}{2} - \frac{1}{2\sqrt{x + 3}} ]

Now, to determine the behavior of ( f(x) ) at ( x = 5 ), we substitute ( x = 5 ) into ( f'(x) ) and evaluate its sign.

[ f'(5) = \frac{(5 + 3)^\frac{-3}{2}}{2} - \frac{1}{2\sqrt{5 + 3}} ]

[ f'(5) = \frac{1}{2\sqrt{8}} - \frac{1}{2\sqrt{8}} = 0 ]

Since the derivative ( f'(5) = 0 ), we cannot determine the increasing or decreasing behavior of ( f(x) ) at ( x = 5 ) from this information alone. We may need to perform further analysis, such as using the second derivative test or examining the function's behavior in the surrounding interval.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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