Is #f(x)=(2x+4)^2-6x-7 # increasing or decreasing at #x=-2 #?
decreasing
f '(x)= 2(2x+4) *2 -6. First, find f '(x). If f '(-2) is positive, then f(x) is increasing; if it is negative, then f(x) is decreasing.
Since f '(-2) = -6, f(x) is decreasing.
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To determine if the function ( f(x) = (2x + 4)^2 - 6x - 7 ) is increasing or decreasing at ( x = -2 ), we need to evaluate the sign of the derivative of the function at that point.
First, find the derivative of ( f(x) ) with respect to ( x ):
[ f'(x) = 2(2x + 4)(2) - 6 ]
[ = 8x + 16 - 6 ]
[ = 8x + 10 ]
Now, evaluate ( f'(-2) ):
[ f'(-2) = 8(-2) + 10 ]
[ = -16 + 10 ]
[ = -6 ]
Since the derivative ( f'(-2) ) is negative, the function ( f(x) ) is decreasing at ( x = -2 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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