Is #-8y = x + 2# a direct variation?

Answer 1
#-8y=x+2# is not a direct variation.
This could be rewritten as #y = (-1/8)x -(1/4)#
But to be a direct variation #y# must be equal to a direct multiple of #x#. That is to be a direct variation, there must be a constant, #m#, such that #y = m*x#
The additional term #-(1/4)# prevents this from being a direct variation.
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Answer 2

No, the equation ( -8y = x + 2 ) is not a direct variation because it cannot be expressed in the form ( y = kx ), where ( k ) is a constant. In direct variation, the equation takes the form ( y = kx ), where ( k ) is a constant called the constant of variation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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