# Is #-8y = x + 2# a direct variation?

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No, the equation ( -8y = x + 2 ) is not a direct variation because it cannot be expressed in the form ( y = kx ), where ( k ) is a constant. In direct variation, the equation takes the form ( y = kx ), where ( k ) is a constant called the constant of variation.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- A point on a graph (-1, -2) that point is located in what quadrant?
- What is the slope intercept form of the line with a slope of #-2/3 # that passes through # (-5,2) #?
- Does the equation #y=-10x# represent a direct variation and if so, identify the constant of variation?
- How to find the x and y-intercept given #y= -2x + 4 #?
- If y varies directly with x, how do you find y when x = 5 if y = -6 when x = 2?

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