Is -3 a solution to the equation #-4x+5=-7#?

Answer 1

No, but #x=3# is a solution.

What results when you substitute -3 into the equation?

#-4 *-3 +5# =#12 + 5# = #17#

Clearly, -3 is not an appropriate solution.

Determine the answer:

Switch the terms around in the equation to:

#-4x#= #-7 -5# = #-12#

Eliminate the negative symbols.

So #x =3 #
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Answer 2

#"No"#

# "if x = - 3 is a solution then it will satisfy the equation" #
#(-4xx-3) + 5 = 12 + 5 = 17! = 7#

"is not a solution" #rArrx=-3

#-4x+5=-7#
# "subtract 5 from both sides" #
#-4xcancel(+5)cancel(-5)=-7-5#
#rArr-4x=-12#
# "divide both sides by" -4#
(-12)/(-4)# = #(cancel(-4) x)/cancel(-4)
#rArrx = 3#
"Check "(-4xx3)+5=-12+5=-7" True"# #color(blue)

"#rArrx=3" is the answer.

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Answer 3

To determine if -3 is a solution to the equation -4x + 5 = -7, we substitute -3 for x in the equation and evaluate if both sides are equal.

Plugging in -3 for x: -4(-3) + 5 = -7 12 + 5 = -7 17 = -7

Since 17 does not equal -7, -3 is not a solution to the equation -4x + 5 = -7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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