In which of the following solution metallic ion can be displaced by aluminium : (i)CuSO4(ii)NaCL(CaCl2(IV)MgSO4 ?

Answer 1

The ions present in solutions are

#Cu^(2+) , Na^(+),Ca^(2+),Mg^(2+)#

The metal dipped in solutions is #Al#

As per the electrochmical series the order of reducing strength of metal is

#Ca >Na >Mg >Al>Cu#

So Al can only reduce #Cu^(2+)# ion from its solution.i.e. Cu only will be displaced from #CuSO_4# solution when Al metal is dipped in it.

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Answer 2

In the given solutions, metallic ions can be displaced by aluminum in solution (i) CuSO4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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