In triangle ABC, how do you solve the right triangle given Side AB=17 Side BC=22?
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Solution:
Let Opposite , adjacent sides of the right triangle be
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To solve the right triangle given Side AB = 17 and Side BC = 22, you can use the Pythagorean theorem and trigonometric ratios.

Find the length of the third side (AC) using the Pythagorean theorem: AC^2 = AB^2 + BC^2 AC^2 = 17^2 + 22^2 AC^2 = 289 + 484 AC^2 = 773 AC ≈ √773

Calculate the angles using trigonometric ratios: Angle A = sin^(1)(opposite/hypotenuse) = sin^(1)(22/√773) Angle B = cos^(1)(adjacent/hypotenuse) = cos^(1)(17/√773)

Angle C is a right angle, so it's 90 degrees.
Now, you have all three sides and angles of the right triangle ABC:
 Side AB = 17
 Side BC = 22
 Side AC ≈ √773
 Angle A ≈ sin^(1)(22/√773)
 Angle B ≈ cos^(1)(17/√773)
 Angle C = 90 degrees
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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