In the equation #N_2 + H_2 -> NH_3#, what mass of ammonia gas can be produced from 12 mol of hydrogen gas?

After that, you can figure out how many moles of ammonia are created by reacting 12 moles of hydrogen. You'll also need a certain amount of nitrogen gas, but that's not the question, so we'll leave it out.

We start by writing what we know from the balanced equation, followed by an equal sign and the question itself:

Multiply "x" by two to find the solution.

Thus, 8 moles of ammonia are produced from 12 moles of hydrogen.

Your final step is to round your response to two significant figures because the question only allows for two.

To find the mass of ammonia gas produced from 12 moles of hydrogen gas, we first need to determine the stoichiometric ratio between hydrogen gas (H2) and ammonia gas (NH3) in the balanced chemical equation.

From the balanced equation: N2 + 3H2 -> 2NH3

We can see that 3 moles of hydrogen gas react with 1 mole of ammonia gas.

Given that there are 12 moles of hydrogen gas, we can use this ratio to find the moles of ammonia gas produced:

Moles of NH3 = (12 moles H2) / (3 moles H2/1 mole NH3) = 4 moles NH3

Now, to find the mass of ammonia gas produced, we use the molar mass of NH3, which is approximately 17.03 g/mol:

Mass of NH3 = Moles of NH3 × Molar mass of NH3 = 4 moles × 17.03 g/mol ≈ 68.12 grams

Therefore, approximately 68.12 grams of ammonia gas can be produced from 12 moles of hydrogen gas.