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In the compound, #CaNa[Fe(CN)_6]#, what ligands are in the coordination sphere?

Answer 1

The coordination sphere you mentioned was not specified.

In #stackrel(+2)"Ca"stackrel(+1)"Na"[stackrel(+3)"Fe " stackrel(-"1 each")(("CN")_6)]# as-written, a mixed calcium-sodium hexacyanoferrate(III) complex:

Now, something doesn't seem right.

Could you mean #"CaNa"_2["Fe"("CN")_6]#, where the first coordination sphere has a #4-# charge instead of a #3-# charge?

In this case, iron(II) would be a #d^6# metal, with a full #t_(2g)# set, i.e. it would be more kinetically inert/stable.

A filled #t_(2g)# set usually implies poor kinetic favorability with electron donors trying to react with it, as they would try to donate into the high-lying (usually antibonding) #e_g# set and increase the antibonding character of the metal-ligand bonds, thus weakening the metal-ligand bonds.

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Answer 2

Olivia Anton

In the compound CaNa[Fe(CN)_6], the ligands in the coordination sphere are cyanide ions (CN^-).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.