In photosynthesis glucose c6h12o6 and o2 are produced from co2 and h2o.

6CO(g)+6H2O(l)+680kcal=C6H12O6(aq)+6O2(g)

How many grams of glucose are produced from 21.0g of CO2?

Question

How to set problem, I believe I'm going from grams to grams

Cameron Andrews · Accepted Answer

#6CO_2(g) + 6H_2O(l) + Delta rarr C_6H_12O_6(aq) + 6O_2(g)# #6CO_2(g) + 6H_2O(l) + Delta rarr C_6H_12O_6(aq) + 6O_2(g)# #"Moles of "CO_2(g)# #=# #(21.0*g)/(44.0*g*mol^-1)# #=# #0.477# #mol# #180.16*g*mol^-1xx1/6xx0.477*mol# #=# #??# #g#

Naomi Aronson · Answer

undefined To find the grams of glucose produced from 21.0g of CO2, we can use stoichiometry:

1 mole of CO2 produces 1 mole of C6H12O6

The molar mass of CO2 is 44.01 g/mol and the molar mass of C6H12O6 is 180.16 g/mol.

First, calculate the number of moles of CO2:
21.0g CO2 * (1 mol CO2 / 44.01 g CO2) = 0.477 moles CO2

Now, using the balanced equation, we see that 1 mole of CO2 produces 1 mole of C6H12O6. Therefore, 0.477 moles of CO2 will produce 0.477 moles of C6H12O6.

Finally, calculate the grams of glucose produced:
0.477 moles C6H12O6 * (180.16 g C6H12O6 / 1 mol C6H12O6) = 85.99 g C6H12O6

So, 21.0g of CO2 produces approximately 86.0g of glucose.

In photosynthesis glucose c6h12o6 and o2 are produced from co2 and h2o. 6CO(g)+6H2O(l)+680kcal=C6H12O6(aq)+6O2(g) How many grams of glucose are produced from 21.0g of CO2?

How to set problem, I believe I'm going from grams to grams