In photosynthesis glucose c6h12o6 and o2 are produced from co2 and h2o.

6CO2(g)+6H2O(l)+680kcal=C6H12O6(aq)+6O2(g)

How much heat in kilojoules is needed to produce 19.5g of c6h12o6?

Question

Not sure how to set up the conversion for the problem

Serenity Allen · Accepted Answer

You need 308 kJ of heat energy.

The equation for thermochemistry is #"6CO"_2 + "6H"_2"O" + "680 kcal" → "C"_6"H"_12"O"_6 + "6O"_2# Your calculation will proceed as follows: 1. Determine the glucose moles. #"Moles of glucose" = 19.5 color(red)(cancel(color(black)("g glucose"))) × "1 mol glucose"/(180.16 color(red)(cancel(color(black)("g glucose")))) = "0.1082 mol glucose"# 2. Determine the caloric value. #"Kilocalories" = 0.1082 color(red)(cancel(color(black)("mol glucose"))) × "680 kcal"/(1 color(red)(cancel(color(black)("mol glucose")))) = "73.60 kcal"# 3. Determine the kilogram-to-joule conversion. #"Kilojoules" = 73.60 color(red)(cancel(color(black)("kcal"))) × "4.184 kJ"/(1 color(red)(cancel(color(black)("kcal")))) = "308 kJ"#

Kai Bowman · Answer

undefined To calculate the amount of heat needed to produce 19.5 g of C6H12O6, we can use the given equation and convert the mass of C6H12O6 to moles, then use the stoichiometry of the reaction to find the amount of heat produced. The molar mass of C6H12O6 is approximately 180.16 g/mol. Then, we can use the given energy value (680 kcal) to determine the heat produced per mole of C6H12O6, and convert it to kilojoules.

In photosynthesis glucose c6h12o6 and o2 are produced from co2 and h2o. 6CO2(g)+6H2O(l)+680kcal=C6H12O6(aq)+6O2(g) How much heat in kilojoules is needed to produce 19.5g of c6h12o6?

Not sure how to set up the conversion for the problem