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In a circle of radius 6, what the length of the arc that subtends a central angle of 242 degrees?

Answer 1

I got #30#

We know that the length of the arc #s# is given as: #s=rtheta# where: #r=# radius; #theta=# angle in radians (#242^@=4.2237 "rad"#).

in numbers we get:

#s=6*4.2237=25.3422~~30#

(1 sig. figure)

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Answer 2

Noah Atkinson

To find the length of the arc that subtends a central angle of ( 242^\circ ) in a circle of radius 6, we use the formula:

[ \text{Arc length} = \frac{\text{central angle}}{360^\circ} \times 2\pi r ]

Substituting the given values:

[ \text{Arc length} = \frac{242^\circ}{360^\circ} \times 2\pi \times 6 ]

[ \text{Arc length} = \frac{121}{180} \times 12\pi ]

[ \text{Arc length} = \frac{121}{15}\pi ]

So, the length of the arc that subtends a central angle of ( 242^\circ ) in a circle of radius 6 is ( \frac{121}{15}\pi ) units.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.