In a certain mystery liquid, the compounds #Al_2S_3#, #K_3N#, #Na_2S#, and #RbBr# each have a value of #Ksp = 1.0 xx 10^-10#. Which of these solids should be the least soluble in the mystery liquid? (Choices in answer).
The answer is indeed A. rubidium bromide
The choices are as follows:
The degree of dissociation of an ionic compound is a measure of its solubility; a more soluble ionic compound will result in higher concentrations of cations and anions in solution.
Examine the dissociation equilibria of the compounds you have.
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Aluminum sulfide (Al2S3) would be the least soluble in the mystery liquid.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- For an equilibrium reaction, how can #K_c#, and #K_P# be related?
- Which one of the following equilibrium reactions corresponds to the β2 constant for the complexation reaction described above? Part a) Ag+(aq) + 2Cn^-1(aq)
- How much #KBr# should be added to #1# #L# of #0.05# #M# #AgNO_3# solution just to start precipitation of #AgBr#? #K_(sp)# of #AgBr# = #5# x #10^-13#.
- At 25°C in a closed system, ammonium hydrogen sulfide exists as the following equilibrium. NH4HS(s)<--->NH3(g) + H2S(g) When a sample of pure NH4HS(s) is placed in an evacuated reaction vessel and allowed to come to equilibrium at 25°C, total pressure is 0.660 atm. What is the value of Kp?
- When I ask my calculator to divide #0.35# by #( 0.15 ) * ( 0.30 )^2# it gives me the result #0.21#. The correct result should be about #26#. What's going wrong?
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