In 1/4 hour, Kyle jogged 2 1/2 mi. Dee jogged 1 3/4 mi in 10 minutes Who ran at a faster rate? What is that rate?

Question

Riley Anderson · Accepted Answer

Doe ran at a faster rate of #10.5# miles per hour.

In #1/4# hour, Kyle jogged #2 1/2=5/2# miles hence in #1# hour, he can jog #5/2xx4=5/(cancel2^1)xxcancel4^2=10# miles Hence, Kyle jogged at a rate of #10# miles per hour. Dee jogged #1 3/4=7/4# miles in #10# minutes As one hour has #60# minutes, in #1# hour, he can jog #7/4xx6=7/(cancel4^2)xxcancel6^3=21/2=10.5# miles. Hence, Doe jogged at a rate of #10.5# miles per hour. Hence Doe ran at a faster rate of #10.5# miles per hour.

Benjamin Altschul · Answer

undefined Dee ran at a faster rate. Her rate was 0.175 miles per minute, while Kyle's rate was 0.1667 miles per minute.

Noah Archer · Answer

undefined To compare their rates, first, convert Dee's jog distance to miles per hour (mph) since Kyle's jog distance is already in mph:

Kyle's rate: $ \frac{2 \frac{1}{2} \text{ mi}}{\frac{1}{4} \text{ hr}} $

Dee's rate: $ \frac{1 \frac{3}{4} \text{ mi}}{\frac{10}{60} \text{ hr}} $

Now, simplify the rates:

Kyle's rate: $ \frac{2.5}{0.25} = 10 \text{ mph} $

Dee's rate: $ \frac{1.75}{\frac{1}{6}} = 10.5 \text{ mph} $

Dee ran at a faster rate of 10.5 mph.