If you have 4 moles each of #CO# and #O_2#, which is the limiting reagent and why?

Answer 1

We need a stoichiometrically balanced oxidation reaction..........

#CO(g) +1/2O_2(g) rarr CO_2(g)#

According to the equation, dioxygen is the reagent in excess and carbon monoxide is the limiting reagent if carbon monoxide and dioxygen are equimolar.

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Answer 2

O_2 is the limiting reagent because it requires twice as many moles of O_2 as CO for complete reaction.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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