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If you add 25 g of sugar to 50 mL of water what would the final mass be?

Answer 1

Well, would not mass be conserved?

You got #25*g# of sugar, and #50*mL# water....of course water has the convenient density of #1*g*mL^-1#, which I am sure you know off the top of your head...and so mass ....

#-=underbrace(25*g)_"mass of sugar"+underbrace(50*mLxx1*g*mL^-1)_"mass of water"=??*g#..

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Answer 2

Mateo Aguilar

The final mass would be #"75 g"#.

The density of water is #"1 g/mL"#. So #"50 mL"# of water has a mass of #"50 g"#. Add the #"25 g"# of sugar, and you get a solution that has a mass of #"75 g"#.

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Answer 3

Owen Ambrose

The final mass would be 75 grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.