# If #y=x^3+2x# and #dx/dt=5#, how do you find #dy/dt# when #x=2# ?

By Implicit Differentiation,

By signing up, you agree to our Terms of Service and Privacy Policy

To find dy/dt when x=2, first find dx/dt=5 at x=2. Then, substitute x=2 and dx/dt=5 into the equation dy/dt = 3x^2(dx/dt) + 2(dx/dt). So, dy/dt = 3(2^2)(5) + 2(5). Calculate this to get the value of dy/dt.

By signing up, you agree to our Terms of Service and Privacy Policy

- How do you find the linearization at a=pi/4 of #f(x)=cos^2(x)#?
- How do you use #f(x) = sin(x^2-2)# to evaluate #(f(3.0002)-f(3))/0.0002#?
- If Newton's Method is used to locate a root of the equation #f(x)=0# and the initial approximation is #x_1=2#, find the second approximation #x_2#?
- How do you use Newton's Method to approximate the value of cube root?
- How do you find the linearization of #f(x) = x^4 + 5x^2# at the point a=1?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7