If y varies inversely with x, and x = -12 when y = 5. How do you find the inverse variation equation and use it to find the value of x when y = 10?

Answer 1

The inverse variation equation is y = k/x, where k is the constant of variation. To find the value of k, we can substitute the given values of x and y into the equation. When x = -12 and y = 5, we have 5 = k/(-12). Solving for k, we get k = -60.

Now that we have the value of k, we can use the inverse variation equation to find the value of x when y = 10. Substituting y = 10 and k = -60 into the equation, we have 10 = -60/x. Solving for x, we get x = -6.

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Answer 2

#y=-60/x,x=-6#

#"the initial statement is "yprop1/x#
#"to convert to an equation multiply by k the constant"# #"of variation"#
#rArry=kxx1/x=k/x#
#"to find k use the given condition"#
#x=-12" when "y=5#
#y=k/xrArrk=xy=-12xx5=-60#
#"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=-60/x)color(white)(2/2)|)))#
#"when "y=10#
#x=-60/y=-60/10=-6#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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