# If Y varies inversely as x^2. If y=2 when x=10, how do you find y when x=5?

To find y when x=5, we can use the inverse variation equation. Since Y varies inversely as x^2, we can write the equation as Y = k/x^2, where k is the constant of variation.

To find the value of k, we can substitute the given values of y=2 and x=10 into the equation: 2 = k/10^2. Solving for k, we get k = 200.

Now, we can use the value of k to find y when x=5. Substituting x=5 and k=200 into the equation, we have Y = 200/5^2. Simplifying, Y = 200/25 = 8.

Therefore, when x=5, y is equal to 8.

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So when x=5 then

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