If y varies directly with x, and y = 0.8 when x = 0.5, how do you write the direct linear variation equation?

Answer 1

#y=1.6x#

#"the initial statement is "ypropx#
#"to convert to an equation multiply by k the constant"# #"of variation"#
#rArry=kx#
#"to find k use the given condition"#
#y=0.8" when "x=0.5#
#y=kxrArrk=y/x=0.8/0.5=1.6#
#" equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=1.6x)color(white)(2/2)|)))#
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Answer 2

The direct linear variation equation is: ( y = kx ), where ( k ) is the constant of variation.

Given that ( y = 0.8 ) when ( x = 0.5 ), we can substitute these values into the equation to find the value of ( k ):

( 0.8 = k \times 0.5 )

Solving for ( k ):

( k = \frac{0.8}{0.5} = 1.6 )

So, the direct linear variation equation is: ( y = 1.6x ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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