# If y varies directly as x and inversely as the square of z and y=1/6 when x=20 and z =6, how do you find y when x = 14 and z=5?

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To find y when x = 14 and z = 5, we can use the direct variation and inverse variation formulas.

First, let's find the constant of variation (k) by substituting the given values into the equation y = kx/z^2.

1/6 = k * 20 / 6^2

Simplifying this equation, we get:

1/6 = k * 20 / 36

Now, solve for k:

k = (1/6) * (36/20) = 3/10

Now that we have the value of k, we can find y when x = 14 and z = 5 by substituting these values into the equation:

y = (3/10) * 14 / 5^2

Simplifying this equation, we get:

y = (3/10) * 14 / 25

y = 42/250

Therefore, when x = 14 and z = 5, y is equal to 42/250.

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