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If #(x-y)= 15#, what is the value of #x^2-2xy+y^2#?

#x^2 -2xy+ y^2 #

Answer 1

Hazel Anglin

#x^2-2xy+y^2=(x-y)^2=15^2=225#

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Answer 2

Kennedy Adams

To find the value of ( x^2 - 2xy + y^2 ), we can use the formula for the square of a binomial:

[ (x - y)^2 = x^2 - 2xy + y^2 ]

Given that ( x - y = 15 ), we can substitute this value into the equation:

[ (15)^2 = x^2 - 2xy + y^2 ]

[ 225 = x^2 - 2xy + y^2 ]

So, the value of ( x^2 - 2xy + y^2 ) is 225.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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