If x varies inversely with y and x = 6 when y = 10, how do you find y when x = 8?

Question

Eli Assouline · Accepted Answer

undefined To find y when x = 8, we can use the inverse variation formula: x1 * y1 = x2 * y2.

Given that x varies inversely with y, we have x1 = 6, y1 = 10, and x2 = 8.

Plugging these values into the formula, we can solve for y2:

6 * 10 = 8 * y2

60 = 8 * y2

Dividing both sides by 8:

y2 = 60 / 8

y2 = 7.5

Therefore, when x = 8, y is equal to 7.5.

Kennedy Adams · Answer

Set up an equation # x = 1/y# substitute to find the constant
# x xx y = C# Then substitute again to find the new y

# x =C?y # # 6 = C/10# multiply both sides by 10 # 6 xx 10 = C/10 xx 10# This gives # 60 = C. # Now substitute x for 8 in the equation and 60 for C # 8 = 60/ y # multiply both sides by y # 8 xx y = 60/y xx y # This gives # 8y = 60# now divide both sides by 8 # 8y/8 = 60/8# The answer is # y = 7.5# As x gets bigger y gets smaller in an inverse relationship.