If x varies inversely as y and y=40 when x=4, how do you find x when y=20?
To find x when y=20, we can use the inverse variation formula: x1 * y1 = x2 * y2.
Given that y varies inversely as x, we have y1 = 40 and x1 = 4.
Plugging these values into the formula, we get: 4 * 40 = x2 * 20.
Simplifying the equation, we have: 160 = x2 * 20.
To find x2, we divide both sides of the equation by 20: x2 = 160 / 20.
Therefore, x2 = 8.
So, when y=20, x=8.
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I didn't understand well the question but I think is about direct and inverse proportion.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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