If water is added to 50 ml of a 0.04M solution so that it fills a 200 mL beaker, what is the final concentration?

Answer 1

Wyatt Atkins

Final concentration #=# #0.01*mol*L^-1#.

#"Concentration"# #=# #"Moles of solute"/"Volume of solution in litres"#

#=# #(50xx10^-3*Lxx0.04*mol*L^-1)/(200xx10^-3L)#

#=# #(50xxcancel(10^-3)*cancelLxx0.04*mol*L^-1)/(200xxcancel(10^-3L))#

#=# #(1xxcancel(10^-3)*cancelLxx0.04*mol*L^-1)/(4xxcancel(10^-3L))#

#=# #0.01*mol*L^-1#

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Answer 2

Wyatt Adkins

The final concentration would be 0.01M.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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