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If two segments AB and CD are in the ratio 3:5 andCD is longer than AB by 28 cm, how long is each segment?

Answer 1

Eva Abramson

#abs(AB) = 42# #cm# and #abs(CD) = 70# #cm#

Lets say that the length of #AB# is #l# and the length of #CD# is #m#.

We are aware of these:

#l/m=3/5#

#m = l+28#

So we can find the value of #l#

Lets replace #m# with #l+28# in the first equation.

#l/(l+28)=3/5#

#5l = 3*(l+28)# #5l = 3l+84# #2l = 84# #l=42# #cm#

Now we know the value of #l#, we knew that #m=l+28# so:

#m = 42+28# #m = 70# #cm#

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Answer 2

Avery Alexander

Let the length of segment AB be (3x) cm and the length of segment CD be (5x) cm. Given that CD is longer than AB by 28 cm, we have:

[5x - 3x = 28]

Solving for (x):

[2x = 28]

[x = 14]

Therefore, the lengths of the segments are:

Length of AB = (3x = 3(14) = 42) cm
Length of CD = (5x = 5(14) = 70) cm

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Answer from HIX Tutor

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