If the volume of a pyramid with a rectangular base is 500, and has a length of 15 and a height of 4, what is its width?
The volume of a pyramid is always one third the area of the base times the height.
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To find the width of the rectangular base of the pyramid, we first need to calculate the area of the base using the given length and height. Then, we can use the formula for the volume of a pyramid to solve for the width.
The area of a rectangle is given by the formula: [ \text{Area} = \text{length} \times \text{width} ]
Given that the length is 15 and the height is 4, we can solve for the width: [ \text{Area} = 15 \times \text{width} = 15\text{width} ]
Now, we can use the formula for the volume of a pyramid, which is given by: [ \text{Volume} = \frac{1}{3} \times \text{base area} \times \text{height} ]
Substitute the known values into the formula: [ 500 = \frac{1}{3} \times (15\text{width}) \times 4 ]
Simplify the equation: [ 500 = \frac{1}{3} \times 60\text{width} ] [ 500 = 20\text{width} ]
Now, solve for the width: [ \text{width} = \frac{500}{20} ] [ \text{width} = 25 ]
Therefore, the width of the rectangular base of the pyramid is 25.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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